0=(x^2-31x-32)/40

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Solution for 0=(x^2-31x-32)/40 equation: 


x in (-oo:+oo)

0 = (x^2-(31*x)-32)/40 // - (x^2-(31*x)-32)/40

0-((x^2-(31*x)-32)/40) = 0

-((x^2-31*x-32)/40) = 0

(-1*(x^2-31*x-32))/40 = 0

x^2-31*x-32 = 0

x^2-31*x-32 = 0

DELTA = (-31)^2-(-32*1*4)

DELTA = 1089

DELTA > 0

x = (1089^(1/2)+31)/(1*2) or x = (31-1089^(1/2))/(1*2)

x = 32 or x = -1

(x+1)*(x-32) = 0

(-1*(x+1)*(x-32))/40 = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-32 )

x-32 = 0 // + 32

x = 32

x in { -1, 32 }

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